Ncert Cbse Class 8 Mathematics Solutions | Linear Equations in One Variable | NCERT Exercise 2.2 Solved (PART – I)

CBSE Mathematics Solutions Class VIII

Ncert Solutions of  8th Maths Exercise 2.2

Linear Equations in One Variable

(page 28)

Q 1: If you subtract 1/2 from a number and multiply the result by 1/2, you get 1/8. What is the number?    

Solution:

Let the number be x. Then by subtracting 1/2 from x and multiplying the result by 1/2 we get, 

Q 2: The perimeter of a rectangular swimming pool is 154 m. Its length is 2m more than twice its breadth. What are the length and breadth of the pool?

Solution:

Let the breadth of the swimming pool be x.

Therefore, its length = 2x + 2

Given the perimeter of the pool = 154 m.

or, 2(2x + 2 + x) = 154

or, 6x + 4 = 154

or,  x = 25m

Hence, Breadth = 25m and

Length = 2 x 25 + 2 = 52m

Q 3: The base of an isosceles triangle is 4/3 cm. The perimeter of the triangle is 4^2/15 cm. What is the length of either of the remaining equal sides?       

Solution: 

Let the length of one equal side of the isosceles triangle be x.

Base of the isosceles triangle = 4/3cm (given)

Q 4: Sum of two numbers is 95. If one exceeds the other by 15, find the numbers.

Solution:

Let one number be x and so, the other number is (x + 15).

or,  x + x + 15 = 95 (sum of the numbers given).

or, x = 40 (and the other number is 40 + 15 = 55)

So, the numbers are 40 and 55 respectively.

Q 5: Two numbers are in the ratio 5 : 3. If they differ by 18, what are the numbers?

Solution:

Let the numbers are x and y

Under the given conditions:

Q 6: Three consecutive integers add up to 51. What are these integers?   

Solution:  

Let the three consecutive integers be x, (x + 1) and (x + 2).

According to the given condition,

x + (x + 1) + (x + 2) = 51

or, x = 16

Therefore the three consecutive integers are 16, 17 and 18 respectively.

Q 7: The sum of three consecutive multiples of 8 is 888. Find the multiples.

Solution:

Let the first multiple of 8 be 8x.

Second multiple be 8x + 8.

Third multiple be 8x + 8 + 8 = 8x + 16.

According to the given condition,

8x + 8x + 8 + 8x + 16 = 888

or, 24x = 864

or, x = 36.

Hence, 8x = 8 x 36 = 288,

8x + 8 = 296,

8x + 16 = 304.

So, the numbers will be 288, 296 and 304.

Q 8: Three consecutive integers are such that when they are taken in increasing order and multiplied by 2, 3, and 4 respectively, they add up to 74. Find these numbers.  

Solution: (Taking hint from Q7 solution do it yourself.)

View solutions of remaining questions visit:

Ncert Math Solutions for CBSE Class 8 | Linear Equations in One Variable | Exercise 2.2 Solved (Q No 9-16)